4x^2=45x

Solution for 4x^2=45x equation:

4x^2=45x

We move all terms to the left:

4x^2-(45x)=0

a = 4; b = -45; c = 0;
Δ = b2-4ac
Δ = -452-4·4·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-45}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+45}{2*4}=\frac{90}{8}
=11+1/4
$